-x^2-4x+65=7

Solution for -x^2-4x+65=7 equation:

-x^2-4x+65=7

We move all terms to the left:

-x^2-4x+65-(7)=0

We add all the numbers together, and all the variables

-1x^2-4x+58=0

a = -1; b = -4; c = +58;
Δ = b2-4ac
Δ = -42-4·(-1)·58
Δ = 248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{248}=\sqrt{4*62}=\sqrt{4}*\sqrt{62}=2\sqrt{62}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{62}}{2*-1}=\frac{4-2\sqrt{62}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{62}}{2*-1}=\frac{4+2\sqrt{62}}{-2}
$